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X^2+X^2=1681
We move all terms to the left:
X^2+X^2-(1681)=0
We add all the numbers together, and all the variables
2X^2-1681=0
a = 2; b = 0; c = -1681;
Δ = b2-4ac
Δ = 02-4·2·(-1681)
Δ = 13448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13448}=\sqrt{6724*2}=\sqrt{6724}*\sqrt{2}=82\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-82\sqrt{2}}{2*2}=\frac{0-82\sqrt{2}}{4} =-\frac{82\sqrt{2}}{4} =-\frac{41\sqrt{2}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+82\sqrt{2}}{2*2}=\frac{0+82\sqrt{2}}{4} =\frac{82\sqrt{2}}{4} =\frac{41\sqrt{2}}{2} $
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